Question 1179089


to graph {{{y-4=3(x+2)}}}, -> you have linear function and graph will be a line

to graph a line all you need is to find two points that lie on this line, plot them and draw a line through


{{{x}}}|{{{y}}}

{{{0}}}|{{{10}}}->{{{y-4=3(0+2)}}}->{{{y-4=6}}}->{{{y=6+4}}}->{{{y=10}}}

{{{-10/3}}}|{{{0}}}->{{{0-4=3(x+2)}}}->{{{-4=3x+6}}}->{{{3x=-4-6}}}->{{{x=-10/3}}}


{{{drawing( 600, 600, -10, 10, -10, 15,
circle(0,10,.12),locate(0.3,10,p(0,10)),
circle(-10/3,0,.12),locate(-10/3,0,p(-10/3,0)),
 graph( 600, 600, -10, 10, -10, 15, 3(x+2)+4)) }}}