Question 1179074
Find the inverse of the one-to-one function.
f(x) = (x - 5)3
write as
y = 3(x-5)
swap x & y and solve for y
3(y-5) = x
y - 5 = {{{x/3}}}
y = {{{x/3}}} + 5
write it
{{{f^-1(x)}}} = {{{x/3}}} + 5