Question 1179033


{{{1/4 < 2/p < 1/3}}}........divide by {{{2}}}


{{{(1/4 )/2< (2/p)/2 < (1/3)/2}}}

{{{1/8< 1/p < 1/6}}}............if so, then

{{{6< p < 8 }}} and =>{{{p=7}}}