Question 1178905
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One of four, &nbsp;then one of two,  &nbsp;and, &nbsp;finally,  &nbsp;one of six gives &nbsp;&nbsp;4*2*6 = 48 &nbsp;&nbsp;different selections.  &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;<U>ANSWER</U> 



Fundamental counting principle.



Lesson

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF =https://www.algebra.com/algebra/homework/Permutations/Fundamental-counting-principle-problems.lesson>Fundamental counting principle problems</A> 

in this site.



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As I treat this problem, &nbsp;it is not about the number of schedules &nbsp;(which term is used here by the author &nbsp;MISTAKENLY),


in my view.  &nbsp;&nbsp;It is about the number of all possible &nbsp;&nbsp;SELECTIONS &nbsp;&nbsp;of the cources.