Question 1178895
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Hi
 
ME ={{{ z*sigma/sqrt(n)}}}, {{{sigma/sqrt(n) = .02/sqrt(50)}}} = .0028
n > 40 and population σ = .02   µ =.995
 99% confidence interval estimate  
ME ={{{2.576*.0028}}} = .0072
.995- .007 < {{{mu}}} < .995 + .007
CI: (.988, 1.002)

95% interval:
ME ={{{1.96*.0028 }}} = .0055 
.995 - .0055< {{{mu}}} < .995 + .0055
CI: (.9895, 1.0055)
CI  is wider at 99%

Wish You the Best in your Studies.
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