Question 1178883
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The *[tex \Large n\text{th}] term is *[tex \Large 4r^{n-1}]


So the fifth term is *[tex \Large 4r^4]


Solve *[tex \Large 4r^4\ =\ 64] for *[tex \Large r]


Then calculate *[tex \Large 4r^{3-1}]

																
John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
*[illustration darwinfish.jpg]

From <https://www.algebra.com/cgi-bin/upload-illustration.mpl> 
I > Ø
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