Question 1178886
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*[tex \Large 2n\ -\ 1] is the *[tex \Large n\text{th}] odd number.  The sum of the first *[tex \Large n] odd numbers is *[tex \Large n^2].


																
John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
*[illustration darwinfish.jpg]

From <https://www.algebra.com/cgi-bin/upload-illustration.mpl> 
I > Ø
*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  
								
{{n}\choose{r}}
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