Question 1178872
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Convert the percent decrease to a decimal.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ Q(t)\ =\ Q_o(r)^t]


Where *[tex \Large Q(t)] is the quantity remaining after *[tex \Large t] hours expressed in the units of measure of the initial quantity, *[tex \Large Q_o] is the initial quantity, and *[tex \Large r] is the rate of decrease expressed as a decimal.


For your second question, evaluate *[tex \Large Q(6)]


																
John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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