Question 994316
n = number of nickels
d = number of dimes
q = number of quarters


n + d + q = 41
5n + 10d + 25q = 495
d = q - 7


Substitute the third equation into the first and second equations.


n + 2q = 48
5n + 35q = 565 ---> n + 7q = 113


n + 2q = 48
-n - 7q = -113
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-5q = -65
q = 13 ---> d = 6 ---> n = 22


There are 22 nickels, 6 dimes, and 13 quarters.