Question 1178705
.
According to the Federal Communications Commission, 70% of all U.S.
households have VCRs. In a random sample of 15 households, what is
the probability that exactly 10 have VCRs?
~~~~~~~~~~~~~


<pre>
It is the binomial type probability distribution.


The number of trial n= 15; the probability of the success trial is  0.7,  and the number of success trial k = 10. 


    P = {{{C[15]^10*0.7^10*(1-0.7)^(15-10)}}} = {{{((15*14*13*12*11)/(1*2*3*4*5))*0.7^10*0.3^5}}} = 0.20613  (rounded).     <U>ANSWER</U>
</pre>

Solved.


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To see many other similar solved problems, look into the lessons

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/Probability-and-statistics/Solving-problems-on-Binomial-distribution-manually.lesson>Simple and simplest probability problems on Binomial distribution</A> 

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/Probability-and-statistics/Typical-binomial-distribution-probability-problems.lesson>Typical binomial distribution probability problems</A> 

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