Question 1178603

{{{f(x) = x^2 - 2x - 5}}}
{{{g(x) = x^2 + 2x + 1}}}


({{{f}}}∘{{{g}}})({{{5}}})

first find 

({{{f}}}∘{{{g}}})({{{x}}})

({{{f}}}∘{{{g}}})({{{x}}})={{{f(g(x))}}}

({{{f}}}∘{{{g}}})({{{x}}})={{{f(x^2 + 2x + 1)}}}

({{{f}}}∘{{{g}}})({{{x}}})={{{(x^2 + 2x + 1)^2-2(x^2 + 2x + 1)-5}}}

({{{f}}}∘{{{g}}})({{{x}}})={{{x^4 + 4x^3 + 4x^2 -6}}}


now find

({{{f}}}∘{{{g}}})({{{5}}})

({{{f}}}∘{{{g}}})({{{5}}})={{{5^4 + 4*5^3 + 4*5^2 -6}}}

({{{f}}}∘{{{g}}})({{{5}}})={{{1219}}}