Question 1178607
{{{f(x) = 3x + 6}}}
{{{g(x) =sqrt(x)}}}


 {{{f}}}∘{{{g}}}={{{f(g(x))}}}

{{{f}}}∘{{{g}}}={{{f(sqrt(x))}}}

{{{f}}}∘{{{g}}}={{{3sqrt(x)+6}}}