Question 110799

Start with the given system

{{{3x+6y=0}}}
{{{x=2/3}}}




{{{3(2/3)+6y=0}}}  Plug in {{{x=2/3}}} into the first equation. In other words, replace each {{{x}}} with {{{2}}}. Notice we've eliminated the {{{x}}} variables. So we now have a simple equation with one unknown.



{{{2+6y=0}}} Multiply



{{{6y=0-2}}}Subtract 6 from both sides



{{{6y=-2}}} Combine like terms on the right side



{{{y=(-2)/(6)}}} Divide both sides by 6 to isolate y




{{{y=-1/3}}} Reduce



So our answer is {{{x=2/3}}}, {{{y=-1/3}}}