Question 1178555


{{{f(x) = -7(x - 8)^2 + 10}}}

it's already written in vertex form {{{f(x) = a(x - h)^2 + k}}} where {{{h}}} and {{{k}}} are coordinates of vertex

as you can see {{{h=8}}} and {{{k=10}}}, so vertex is at ({{{8}}},{{{10}}})