Question 1178485
the nth term formula of the geometric sequence:

{{{a[n]=a[1]*r^(n-1)}}} where {{{n}}}={{{1}}}, {{{2}}},.......

given:

sequence: {{{5}}}, {{{15}}}, {{{45}}},. . .

 {{{a[1]=5}}}
 {{{a[2]=15}}}
{{{a[3]=45}}}

so, you multiply first term by {{{3}}} to get second term, and multiply second term by {{{3}}} to get third term

so, common ratio is {{{r =3}}}

your formula is:

{{{a[n]=5*3^(n-1)}}}

find:

{{{a[17]}}}=> means {{{n=17}}}

{{{a[17]=5*3^(17-1)}}}

{{{a[17]=5*3^16}}}

{{{a[17]=215233605}}}