<PRE><B>Question 1178438</B>
.
There is an animal farm where chickens and cows live. All together, there are 47 heads and 164 legs. 
How many chickens and cows are there on the farm?
~~~~~~~~~~~~~~


&lt;pre&gt;
x cows and (47-x) chicken


The total number of legs equation is


    4x + 2(47-x) = 164.


From the equation,


    x = {{{(164 - 2*47)/(4-2)}}} = 35.


&lt;U&gt;ANSWER&lt;/U&gt;.  35 cows and 47-35 = 12 chicken.


&lt;U&gt;CHECK&lt;/U&gt;.  35*4 + 12*2 = 164 total legs.   ! Correct !
&lt;/pre&gt;

Solved.


-------------------


To see many other similar &amp;nbsp;(and different) &amp;nbsp;solved problems, &amp;nbsp;look into the lessons

&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;- &lt;A HREF=http://www.algebra.com/algebra/homework/word/misc/Problem-on-two-wheels-and-three-wheels-bicycles-in-a-sale.lesson&gt;Problem on two-wheel and three-wheel bicycles&lt;/A&gt;

&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;- &lt;A HREF=http://www.algebra.com/algebra/homework/word/misc/Problem-on-animals-at-a-farm.lesson&gt;Problem on animals at a farm&lt;/A&gt;

&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;- &lt;A HREF=http://www.algebra.com/algebra/homework/word/misc/Problem-on-tablets-in-containers.lesson&gt;Problem on pills in containers&lt;/A&gt;

&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;- &lt;A HREF=http://www.algebra.com/algebra/homework/word/misc/What-type-of-problems-are-these.lesson&gt;What type of problems are these?&lt;/A&gt; 

at this site.



</PRE>