Question 1178424
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If the solid has a circular base, then it is a cone or a cylinder.  Since the intersection of a plane perpendicular to a given diameter of the base and the solid is a square, then the solid must be a right circular cylinder, and furthermore, the height must be equal to the measure of a diameter.  That is to say *[tex \Large h\ =\ 2r].


The formula for the volume of a right circular cylinder is:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ V\ =\ \pi{r^2}h]


Substitute *[tex \Large 2r] for *[tex \Large h] and simplify.

																
John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
*[illustration darwinfish.jpg]

From <https://www.algebra.com/cgi-bin/upload-illustration.mpl> 
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