<PRE><B>Question 1178395</B>
&lt;br&gt;
Let the three circles, from largest to smallest, be A, B, and C, with radii a, b, and c, respectively.  Then&lt;br&gt;
a+b=14
a+c=12
b+c=10&lt;br&gt;
Add those three equations:&lt;br&gt;
2a+2b+2c=36
a+b+c=18&lt;br&gt;
From that equation and the earlier three equations, we find a=8, b=6, c=4.&lt;br&gt;
So the radius of the largest circle is 8, and so its area is 64pi.&lt;br&gt;
ANSWER: 64pi&lt;br&gt;
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