Question 1178316
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4 - (4/n) + (5/n) + (15/(3n^2))



                Please notice how I rewrote your post using parentheses.


                I did it to show different parts of formulas in clear way.



<pre>
There is a constant term of 4, and 3 other terms, containing  {{{n}}}  and  {{{n^2}}}  in their denominators.


These three terms tends to zero as n tends to infinity.


THEREFORE, the limit is 4 when n approaches  infinity.
</pre>

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Is something that is unclear to you in my explanation ?



&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;Next time, as you post to this forum, use parentheses to show clearly different parts of the formulas, 

&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;their numerators and denominators.



&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;Otherwise, your posts will be UNREADABLE at this forum.