Question 1178227
A1=8, ak +1 = ak+6

let k=1, a2 =a1+6 = 8+6=14

k=2 , a3 = a2+8 14+6 =20

so the first five terms= 8,14,20,26,32
common difference =6

an= a1+(n-1)d = 8+(n-1)6