Question 1178176
<br>
•P(n,n-1)=6<br>
P(n,n-1) has the same value as P(n,n), which is n!:<br>
P(n,n-1) = n(n-1)...(3)(2) = n(n-1)...(3)(2)(1) = n!<br>
So the first problem is<br>
n! = 6<br>
Trivially, the answer is n=3.<br>
•P(16,4)=208•P(n,2)<br>
{{{16*15*14*13 = 208*(n(n-1))}}}
{{{16*15*14*13 = 16*13(n(n-1))}}}
{{{15*14 = n(n-1)}}}<br>
Clearly n=15.<br>