Question 1178173
{{{2x+ 3y = 4}}}....eq.1
{{{5x - 5y = -15}}}....eq.2
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{{{2x+ 3y = 4}}}....eq.1, solve for {{{x}}}
{{{2x= 4-3y }}}
{{{x= 2-3y/2 }}}


go to

{{{5x - 5y = -15}}}....eq.2, substitute {{{x}}}

{{{5(2-3y/2) - 5y = -15}}}....solve for {{{y}}}

{{{ 10 - (25y)/2= -15}}}

{{{ 25 - (25y)/2=0}}}

{{{ 25=(25y)/2}}}

{{{ 50=25y}}}

{{{ y = 50/25}}}

{{{ y = 2}}}

go to

{{{x= 2-3y/2 }}}..., substitute {{{y}}}

{{{x= 2-(3*2)/2 }}}

{{{x= 2-3}}}

{{{x= -1}}}



Answer: ({{{x}}},{{{y}}}) =({{{-1}}},{{{2}}})