Question 1178125
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Hi
Population is normally distributed.
Sample n = 10  mean = 11.29  and s = 2.33
95% confidence interval:  df = 9 , t = 2.262
ME ={{{ z*sigma/sqrt(n)}}} = 2.262*2.33/√10 = 1.7
11.29 - 1.7 < {{{mu}}} < 11.29 + 1.7
 9.59< {{{mu}}} < 12.99
CI:  ( 9.60, 13.00) Rounded to nearest tenth.
As to Answers, obviously rounding off to the nearest 10th.

Wish You the Best in your Studies.
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