Question 1178132
1. Given:AB=(3x-5)cm,BC=(2y-7)cm,CD=(X+7)cm and AD=(y+3)cm.

AB=CD, BC =AD opposite sides of parallelogram
AB=(3x-5)cm,BC=(2y-7)cm,CD=(X+7)cm and AD=(y+3)cm.

(3x-5)=(X+7) .
2x=12
x=6
a.what is the value of x? x=6
b.how long is AB?
AB=3x-5 = 13

c.what is the value of y?
2y-7 =y+3
y=10
d.how long is AD? y+3 . AD=13
e.how did you solve for the values of x and y?
f.what property did you apply to determine the lengths of AB and AD?
AB=CD, BC =AD opposite sides of parallelogram

2.BAD measures (2a+25)° while BCD measures (3a-15)°
(2a+25)° =(3a-15)°
a=40 deg

a.what is the value of a? 40 deg
b.what is the m BAD = 2a +25 =105 deg

c.what is the m CBA?
m CBA = 75 deg
e.how did you find the value of a?
mBAD + mA CBA=180 deg 
 
f.what property did you apply to solve for m CBA?
Adjacent angles of a parallelogram are supplementary