Question 1178109
s=-16t^2+vt+s0
156=-16+v+s0; v+s0=172
108=-64+2v+s0; 2v+s0=172; therefore v=0 and s0=172
28=-144+3v+s0; 3v+s0=172
The equation is s(g)=-(1/2)at^2+172
{{{graph(300,300,-1,5,-20,200,-16x^2+172,156,108,28)}}}

It is dropped from a height of 172 feet.