<PRE><B>Question 1178012</B>
&lt;br&gt;
Part 1: find t.&lt;br&gt;
From P to Q is 3 units right and 6 units down; the slope of PQ is -2.&lt;br&gt;
PQR is a right angle, so the slope of QR is +1/2.  That means on QR the change in y is 1/2 the change in x -- i.e., the change in x is 2 times the change in y.&lt;br&gt;
From Q to R the change in y is -2, so the change in x has to be -4.  A change of -4 in x and a change of -2 in y from Q(2,5) puts us at R(-2,3).&lt;br&gt;
ANSWER: t = -2.&lt;br&gt;
Part 2: Find the coordinates of point S.&lt;br&gt;
S is on PQ extended, and QS = PQ.&lt;br&gt;
From P to Q was 3 units right and 6 units down; from Q to S will be the same.&lt;br&gt;
3 right and 6 down from Q(2,5) puts us at S(5,-1).&lt;br&gt;
ANSWER: S is (5,-1).&lt;br&gt;
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