Question 1177951
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The only possible rational roots are of the form (plus or minus) p/q, where p is a factor of the constant term and q is a factor of the leading coefficient.  So in this polynomial the only possible rational roots are -2, -1, 1, and 2.<br>
Simple quick substitution shows that none of those are roots.<br>
It is a 4th degree polynomial, so there are 4 roots; and we now know they are all irrational.  So they can only be determined approximately by numerical methods such as calculus or a graphing calculator.<br>