Question 1177870
<font face="Times New Roman" size="+2">


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ a\ +\ bi]


in polar form is *[tex \Large \(r,\theta\)]


Where *[tex \Large r\ =\ \sqrt{a^2\,+\,b^2}] and *[tex \Large \theta\ =\ \tan^{-1}\(\frac{b}{a}\)].  For your problem, since *[tex \Large a] and *[tex \Large b] are both negative, *[tex \Large \theta\ \in \text{QIV}]


																
John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
*[illustration darwinfish.jpg]

From <https://www.algebra.com/cgi-bin/upload-illustration.mpl> 
I > Ø
*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  
								
{{n}\choose{r}}
</font>