Question 1177877
Mary is twice as old as Hilda. Four years from now the sum of their ages will be 41. Find their present age.
 
Let Hilda's age be x

Mary's age will be 2x

2x+4 +x+4 = 41

3x+8 =41

3x=41-8

3x =33
x=11
Hilda's age 11 years
Mary's age = 2x = 22 years