Question 1177877
Mary is twice as old as Hilda.
let h = Hilda's age
then, since Mary is twice as old:
2h = Mary's age
 Four years from now the sum of their ages will be 41.
(h+4) + (2h+4) = 41
h + 2h + 4 + 4 = 41
3h + 8 = 41
3h = 41 - 8
3h = 33
h = 33/3
h = 11 yrs old is Hilda's age
then
2*11 + 22 is Mary's age
:
:
Check their age total in 4 yrs
11 + 4 = 15
22 + 4 = 26
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tot age 41