Question 1177763
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Hi
 standard normal Distribution:    μ = 0   σ  = 1


 P(z > z0 = .05   invNorm(.05) =  1.645 = z0  small area to right 
(b) P(Z < z0) = 0.88  invNorm(.88) = 1.175= z0  large area to the left
(c) P(Z < z0) = 0.10  invNorm(.10) = -1.282= z0 small area to the left
(d) P(Z > z0) = 0.95.   invNorm(.95) = -1.645= z0 large area to right
Wish You the Best in your Studies.
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