Question 1177787


the area original uncut box is {{{51}}}cm by {{{45}}}cm

you deduct {{{2x}}} from the length and from the width

then the volume will be

{{{V=x(51-2x)(45-2x)}}}

given that {{{V=7175cm^2}}}

{{{7175=x(51-2x)(45-2x)}}}...expand and solve for {{{x}}}

{{{4x^3 - 192x^2 + 2295x - 7175 = 0}}} ......using calculator, we get

{{{x=5}}}

then dimensions of the box are

{{{51-2x=51-10=41}}}-> length
{{{45-2x=45-10=35}}}->width
{{{x}}}->height

check:

{{{7175=x(51-2x)(45-2x) }}}
{{{7175=5(41)(35) }}}
{{{7175=7175}}}