Question 1177771


sin b = 5/13

cos b = —12/13

tan b = —5/12

sin2b = —120/169

cos 2b = 2 cos^2 b —1 = 288/169 —1 = 119/169

tan 2 b = —5/6 / 1-25/144 = — 120/144 / 119/144

= -120/119