Question 1177757


Standard form of the tangent function is

{{{y=Atan(Bx-C)+D}}}

where

 {{{A }}}is amplitude

{{{B}}} is the period, determines how wide or narrow the graph is 

{{{C}}} is phase shift, determines  how the graph is shifted from left to right

{{{D}}} is the vertical shift, determines  how the graph is shifted up or down 


given:

 period ={{{5pi}}} and phase shift={{{pi/2}}}


periodicity of tan is{{{ pi}}}

{{{period =pi/B}}}

{{{5pi=pi/B}}}

{{{B=pi/5pi}}}

{{{B=1/5}}}


{{{phase_ shift =C/B}}}

{{{pi/2 =C/(1/5)}}}

{{{(pi/2) (1/5)=C}}}

{{{C=pi/10}}}

your equation is:

{{{y=tan((1/5)x-pi/10) }}}