Question 110715
One little error set you off a bit.
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{{{f(x)=x^2-4x+3}}}
{{{f(-1)=(-1)^2-4(-1)+3}}}
{{{f(-1)=1-4(-1)+3}}}
{{{f(-1)=1+4+3=8}}}:  Here is where you moved a 3 down as the value of the first term instead of the 1 it should have been.
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And then the correct ordered pair, (x,f(x)) would be (-1,8)
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