Question 1177666


Write the equation of this geometric sequence and find the value of the 9th term. 

{{{1/3}}}, {{{1}}}, {{{3}}},{{{ 9}}}... {{{f(n) = f(9)}}} =


{{{f[n] = f[1]*r^(n-1)}}} where {{{f[1]}}} is the first term, {{{f[n]}}} is the nth term,{{{ r}}} is the common ratio, and {{{n}}} is the number of terms


given:

{{{f[1]=1/3}}}

{{{f[2]=1 }}}

find {{{r}}}


{{{r=f[2]/f[1]=1/(1/3)=3}}}


formula is

{{{f[n] = (1/3)*3^(n-1)}}}


find {{{f(9)}}} => {{{n=9}}}


{{{f[9] = (1/3)*3^(9-1)}}}

{{{f[9] = (1/3)*3^8}}}

{{{f[9] = 2187}}}