Question 1177647
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Hi
(−7, −7) 3rd quadrant
 r = sqrt(x^2 + y^2) = sqrt(98) =  ±  7√2
for the point for 0 ≤ 𝜃 < 2𝜋
tan θ = 1  Look below:  θ is 5π/4 (3rd quadrant)  0r 5π/4 - π = π/4 if r< 0 
two sets of polar coordinates: (r,θ) 
(7√2, 5π/4) and (-7√2, π/4) 
Wish You the Best in your Studies
(cos, sin)  Unit Circle:
     *[illustration wheel].
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