Question 1177626
The product of three integers is 90.
let the numbers be x,y,z
The second number is twice the first number.
y = 2x

The third number is two more than the first number. 
z = x+2
Substitute for y and for z and solve for x
x(2x)(x+2) = 90
2x^3+4x^2-90 = 0
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x^3 + 2x^2 - 45 = 0-
 graph the cubic and you will get a solution   x = 3
 y = 2x = 6
z = x+2 = 5