Question 1177601
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            Having the solution,  as it is written and presented in the post by @josgarithmetic, 

            I feel the need to  REWRITE  it from the scratch,


            since his presentation is below any acceptable level.



<pre>
Let x be the car's rate, in miles per hour.


Then the car's time traveled is   {{{T[car]}}} = {{{30/x}}}  hours.


According to the condition, then the train's time traveled is  {{{T[train]}}} = {{{(5/6)*T[car]}}} = {{{(5/6)*(30/x)}}} = {{{25/x)}}}  hours.


Thus the train's rate is  {{{30/T[train]}}} = {{{30/((25/x))}}} = {{{(6x)/5}}}.


We are given  that the difference of rates is 8 miles per hour.  It means


    {{{(6x)/5}}} - x = 8.


To solve this equation, multiply both sides by 5.  You will get


    6x - 5x = 40

       x    = 40.


Thus the rate of the car is 40 miles per hour.
</pre>

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Solved and presented in a way, &nbsp;&nbsp;<U>as &nbsp;it &nbsp;SHOULD &nbsp;be &nbsp;DONE</U>.