Question 110078
Find two positive real numbers that differ by 1 
x, x+1
:
have a product of 1.
x(x+1) = 1
x^2 + x = 1
:
Solve this by completing the square:
x^2 + x + ___ = 1
:
x^2 + x + .25 = 1 + .25
:
(x + .5)^2 = 1.25
:
x + .5 = +/-{{{sqrt(1.25)}}}
:
x = -.5 + {{{sqrt(1.25)}}} ~ +.618
and
x = -.5 - {{{sqrt(1.25)}}} ~ -1.618
:
Try them both in the original equations