Question 697748
consecutive negative integers: x, (x+1)


x(x+1) = 48 + 3x
x^2 + x = 48 = 3x
x^2 - 2x - 48 = 0
(x - 8)(x + 6) = 0
x = 8, x = -6


x is negative ---> integers: -6, -5