Question 1177562
<br>
"log base 2 OF 3", not "log base 2 to 3"....<br>
{{{log(2,(8/135)))}}}
= {{{log(2,((2^3)/((3^3)(5))))}}}
= {{{3log(2,2)-(3log(2,3)+log(2,5))}}}
= {{{3(1)-(3x+y)}}}
= {{{3-3x-y}}}<br>