Question 110622
{{{(5+y)/(y-3)=14/10}}}
:
The process here involves the fact that if {{{p/q=r/s}}} then {{{ps=qr}}}
:
Therefore, we can write:
:
{{{10(5+y)=14(y-3)}}}
:
{{{50+10y=14y-42}}}
{{{50+42=14y-10y}}}
{{{4y=92}}}
{{{y=23}}}
:
Check:
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Does {{{(5+23)/(23-3)=14/10}}}?
{{{28/20=14/10}}}, check.