Question 110631
(-3,-2)
(-1,0)
(1,2)
if you were to connect these points with a line, where would the y-intercept be located?
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Pick a couple of points and find the equation of the line thru them.
Using (1,2) and (-1,0)
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slope = [2-0]/[1--1] = 2/2 = 1
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Form y=mx+b
Substitute to find "b":
2 = 1*1+b 
b = 1
EQUATION: y = x+1
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The y-intercept is (0,1)
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Cheers,
Stan H.