<PRE><B>Question 1177486</B>
&lt;br&gt;
Draw perpendicular AE from A to side CD.&lt;br&gt;
Let CE=x so BE=132-x; let the length of AE be y.&lt;br&gt;
Then right triangles AEC and AEB give us&lt;br&gt;
{{{x^2+y^2 = 37^2}}}  [1]
{{{(132-x)^2+y^2 = 125^2}}}  [2]&lt;br&gt;
Expand [2]:&lt;br&gt;
{{{132^2-264x+x^2 = 125^2}}}  [3]&lt;br&gt;
Subtract [1] from [3]:&lt;br&gt;
{{{132^2-264x = 125^2-37^2}}}&lt;br&gt;
Use a calculator and basic algebra to find x; then use [1] to find y.&lt;br&gt;
Then the area of the parallelogram is base times height, which is 132 times y.&lt;br&gt;
One of the given answer choices is correct....&lt;br&gt;
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