Question 1177488

 the slope-intercept equation of a line 

{{{y=mx+b}}}

if the line is perpendicular to {{{y=3x-4}}}, which has a slope {{{3}}}, it will have a slope negative reciprocal to {{{3}}} and it will be {{{-1/3}}}

so far equation of the  perpendicular line is

{{{y=-(1/3)x+b}}}

 and if a line goes through the point ({{{6}}},{{{2}}}), use it to calculate {{{b}}}

{{{2=-(1/3)6+b}}}

{{{2=-2+b}}}

{{{2+2=b}}}

{{{b=4}}}


and equation is

{{{y=-(1/3)x+4}}}



{{{drawing( 600, 600, -10, 10, -10, 10,
circle(6,2,.12), locate(6,2,p(6,2)),
 graph( 600, 600, -10, 10, -10, 10, -(1/3)x+4, 3x-4)) }}}