Question 741915
x = y + 3
2y^2 + 3x = 74


Substitute x = y + 3 into the second equation.


2y^2 + 3(y + 3) = 74
2y^2 + 3y + 9 = 74
2y^2 + 3y - 65 = 0
(y - 5)(2y + 13) = 0
y = 5, y = -13/2


y is a positive integer, so the integers are (x, y) = (8, 5)