Question 791444
 consecutive integers such that five times the third integer equals twice the first integer plus seven more than the second integer?
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{{{system(n-1,n,n+1)}}}


{{{5(n+1)=2(n-1)+n+7}}}

{{{5n+5=2n-2+n+7}}}


-----------------------the rest of these steps were wrong------------------
{{{cross(2n+5=-2+7)}}}

{{{cross(2n=10)}}}

{{{cross(n=5)}}}


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<s>The integers are 4,5,6</s>
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