Question 1177390

assuming {{{2x+9 }}} is a factor


{{{(2x^3+9x^2-4x-18)/(2x+9)}}}

{{{((2 x + 9) (x^2 - 2))/(2x+9)}}}

so,

{{{2x^3+9x^2-4x-18=(x^2 - 2)(2x+9)}}}

zeros:

{{{(x^2 - 2)(2x+9)=0}}}

if {{{(x^2 - 2)=0}}}=>{{{x^2 = 2}}} => {{{x=sqrt(2)}}} or {{{x= -sqrt(2) }}}
or

if {{{2x+9=0}}} =>{{{2x=-9}}} =>{{{x=-9/2}}}