Question 751633
consecutive positive integers: (x-1), x, (x+1)


(x-1)(x) = 5(x+1) - 5
x^2 - x = 5x
x^2 - 6x = 0
x(x - 6) = 0
x = 0, x = 6


x is positive, so the integers are 5, 6, and 7.